1. Prove, by induction, that for every positive integer n,
Base case, n=1,
Then I could write is as
I have no idea how to proceed.
Last edited by yzc717; Sep 15th 2009 at 09:27 PM.
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If we assume that means
So times it by 4 for and there you go.
Originally Posted by Matt Westwood If we assume that means
So times it by 4 for and there you go. so all we cares about is the 4^n, it is always divisible by 6, the constant doesn't matter?
No, 4^n always leaves a remainder 4 when divided by 6. As 14 leaves a remainder 2 when divided by 6, so add them together and the sum is then divisible by 6.
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