Thread: Another finite question I need help with please

Assume that X={B,D,G,C} and Y={5,7,4,3}. A code consists of 2 different symbols selected from X followed by 3 not necessarily different symbols from Y. How many different codes are possible?

Thank you so much to whoever ends up helping me out!

Only have like 15 minutes before this is due, please help me ASAP

Don't worry about it now guys. It's past due now.

It's probably not a good idea to wait until only 30 minutes are left and expect people to be waiting to answer your question!

In any case, since there are 4 symbols in X, there are 4 ways to select the first symbol and then 3 different ways to select the next symbol. Since there are 4 symbols in Y, and you can use the same symbol over again, there are 4 ways to select each of the last 3 symbols. By the "fundamental counting principal", there are 4(3)(4)(4)(4)= 768 ways to do that.