Only have like 15 minutes before this is due, please help me ASAP
Assume that X={B,D,G,C} and Y={5,7,4,3}. A code consists of 2 different symbols selected from X followed by 3 not necessarily different symbols from Y. How many different codes are possible?
Thank you so much to whoever ends up helping me out!
It's probably not a good idea to wait until only 30 minutes are left and expect people to be waiting to answer your question!
In any case, since there are 4 symbols in X, there are 4 ways to select the first symbol and then 3 different ways to select the next symbol. Since there are 4 symbols in Y, and you can use the same symbol over again, there are 4 ways to select each of the last 3 symbols. By the "fundamental counting principal", there are 4(3)(4)(4)(4)= 768 ways to do that.