hi,

Given the equation below, it a pole of order 5 when z = 0

f(z) = sin(z)/z^6

Question--> I can't seem to get how to achieve the pole. The answer was given by the prof so i assume it's right.

Why is it not RS when we apply limit z => 0 ? isn't the whole equation set out to be 0 , then using L'hopital rule to find the answer?

Thanks