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Math Help - prove that (arctan x)<x if x is positive

  1. #1
    Senior Member
    Joined
    Feb 2008
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    410

    prove that (arctan x)<x if x is positive

    It seems like this should be a fairly simple thing, yet I can't seem to pin down the trick.

    Hi, all. I need to prove that if x>0, then \tan^{-1}x<x.

    Any ideas?

    POTENTIALLY USELESS INFO: This is in order to prove that \{x_n\} recursively defined by x_{n+1}=\tan^{-1}x_n \forall n\geq 0 and x_0>0 converges to a finite limit.

    Thanks!
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  2. #2
    Junior Member
    Joined
    Aug 2009
    Posts
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    x - arctan(x) is continuous and is 0 at 0, its derivative is 1 - 1/(1+x^2) which is positive when x>0 .... I see no problem here, it is an increasing function.
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