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Math Help - Power Series

  1. #1
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    Power Series

    Can anyone tell me how

     \sum_{n=1}^{\infty }\frac{(-1)^{n}}{n3^{n}}(2-5)^{n}=\sum_{n=1}^{\infty }\frac{1}{n} ?

    and also how to get this expression typed in LaTex to appear correctly?
    [tex] \sum_{n=1}^{\infty }\frac{(-1)^{n}}{n3^{n}}(2-5)^{n}=\sum_{n=1}^{\infty }\frac{1}{n}[/tex]
    Last edited by Plato; August 25th 2009 at 07:58 AM. Reason: LaTex fix
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  2. #2
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    Quote Originally Posted by tashbo View Post
    Can anyone tell me how

     \sum_{n=1}^{\infty }\frac{(-1)^{n}}{n3^{n}}(2-5)^{n}=\sum_{n=1}^{\infty }\frac{1}{n} ?
    Note that (2-5)^n=(-3)^n=(-1)^n(3^n)
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