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Math Help - real analysis

  1. #1
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    real analysis

    Let c>1 and  m,n \in N \mbox  { with } \   m>n :<br />
\\\\\\\\\\\mbox {prove that} \ {c^m}> {c^n}
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  2. #2
    Member Mauritzvdworm's Avatar
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    Since m > n we have and c>1
    c^{m-n}>1 so we can then proceed in the following way
    c^{m}c^{-n}c^{n}>1c^{n}
    c^{m}>c^{n}
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