Let c>1 and $\displaystyle m,n \in N \mbox { with } \ m>n : \\\\\\\\\\\mbox {prove that} \ {c^m}> {c^n} $
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Since m > n we have and c>1 $\displaystyle c^{m-n}>1$ so we can then proceed in the following way $\displaystyle c^{m}c^{-n}c^{n}>1c^{n}$ $\displaystyle c^{m}>c^{n}$
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