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Thread: real analysis

  1. #1
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    real analysis

    Let c>1 and $\displaystyle m,n \in N \mbox { with } \ m>n :
    \\\\\\\\\\\mbox {prove that} \ {c^m}> {c^n} $
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  2. #2
    Member Mauritzvdworm's Avatar
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    Since m > n we have and c>1
    $\displaystyle c^{m-n}>1$ so we can then proceed in the following way
    $\displaystyle c^{m}c^{-n}c^{n}>1c^{n}$
    $\displaystyle c^{m}>c^{n}$
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