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Thread: real analysis

  1. August 19th 2009, 11:48 AM #1
    flower3
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    real analysis

    Let c>1 and m,n \in N \mbox { with } \ m>n :<br /> \\\\\\\\\\\mbox {prove that} \ {c^m}> {c^n}
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  2. August 19th 2009, 12:44 PM #2
    Mauritzvdworm
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    Since m > n we have and c>1
    c^{m-n}>1 so we can then proceed in the following way
    c^{m}c^{-n}c^{n}>1c^{n}
    c^{m}>c^{n}
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