F(X)= 1, 0<X<1 2-x 1<X<2 I need to extend f as an odd function over [-2,2] and find the fourier sine series, Then i need to extend f as an even functun over [-2,2] and find the fourier cosine series,
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Originally Posted by sazzy3 F(X)= 1, 0<X<1 2-x 1<X<2 I need to extend f as an odd function over [-2,2] and find the fourier sine series, Then i need to extend f as an even functun over [-2,2] and find the fourier cosine series, What have you done? Odd extension: $\displaystyle F(x) = \begin{cases} -(2+x) & -2<x<-1 \\ -1 & -1<x<0 \\ 1 & 0<x<1\\ 2-x& 1<x<2 \end{cases}$ CB
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