i using but the answer not the same
The redisue theorem will only work when you are integrating over some closed positively oriented contour where the function you want to integrate is analytic inside and on the contour except at say points
we can then write the answer in the following way
Now since the function you want to integrate is analytic everywhere the answer to your integral should be zero but there might be trick here, try decomposing the function in the following way
First, by a bit of elementary algebra, simplify the integral to . Next, identify the poles inside the unit circle by factorising the denominator. It is a quadratic in , with roots . As luck would have it, , so the denominator has four roots .
Now for a quotient of the form , the residue at a simple root of is given by . In this case and . So the residue at is . The poles inside the unit circle are given by . For both of these, and so the residue is .
Finally, the integral is equal to times the sum of the two residues, namely .