From the law the fact that and the fact that you should be able to prove the first part easily.

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- July 10th 2009, 11:14 AM #1

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## please help me

use complex analysis to factor the following polynomials into a product of two quadratic polynomials:

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sketch :

and determine if the set is :

open,closed,bounded,connected ,simply connected , domain,compact or region

answer :

the given set is :

closed,connected ,simply connected ,and region

but not :

open,bounded,domain,and compact

my question : if the question : arg z not Arg z"principle argument" the answer is the same or not ???

- July 10th 2009, 02:55 PM #2

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- July 11th 2009, 08:05 PM #3

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- July 11th 2009, 09:49 PM #4

- July 12th 2009, 04:59 AM #5
I suspect the OP meant two quadratic polynomials

*with real coefficients*.

Unfortunately, in an exam setting, if the question gives the instruction to use complex analysis then a correct answer using an alternative technique will not score any marks. Not even an answer mark.

Start by finding the four complex roots of -1. Can you do this? (If not, see http://www.mathhelpforum.com/math-he...ex-number.html, for example).

- July 12th 2009, 05:19 AM #6

- July 12th 2009, 11:56 AM #7

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- July 12th 2009, 12:00 PM #8

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- July 12th 2009, 06:23 PM #9