If be the complex numbers represented by the vertices of a triangle in anticlockwise order, show that:
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About LinkBacksbe the complex numbers represented by the vertices
of a triangle
in anticlockwise order, show that:
![\left|\sum \frac{z_2 - z_3}{z_1}|z_1|^2\right|\cos A - 2R[(z_1 - z_2)(\bar{z_1} - \bar{z_2})]\sin A = 0](http://latex.codecogs.com/png.latex?\left|\sum \frac{z_2 - z_3}{z_1}|z_1|^2\right|\cos A - 2R[(z_1 - z_2)(\bar{z_1} - \bar{z_2})]\sin A = 0)
