Hi, can somebody please show me how to find the following Taylor series expansion? $\displaystyle (3+2x)^\frac{1}{3}$ (about x=0).

I get that f(0)=$\displaystyle 3^\frac{1}{3}$

f'(0)=$\displaystyle \frac{1}{3} 3^\frac{-2}{3}$

f''(0)=$\displaystyle \frac{-2}{9} 3^\frac{-5}{3}$

etc...

and I know that f(x)=f(0)+f'(0)x+ f''(0)x^2/2! + ...

but I am having a lot of trouble writing it as a sum. Any ideas?