But it's $\displaystyle \sum_{n=0}^{\infty}$ not $\displaystyle \sum_{x=0}^{\infty}$ so it should be alright....shouldn't it?

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- May 19th 2009, 07:17 AMShowcase_22
But it's $\displaystyle \sum_{n=0}^{\infty}$ not $\displaystyle \sum_{x=0}^{\infty}$ so it should be alright....shouldn't it?