Since the partial derivatives are continuous, the function is differentiable. Further, the limits, as (x, y) go to 0, are 0.
So the only question is at (0,0).
Since those match the limits of the partial derivatives as (x, y) goes to (0,0), the function is also differentiable at (0,0).
Again, that shows that the partial derivatives exist and are continuous at (0,0). That implies that the function is differentiable at (0,0).
I am not sure with the continuous bit.
as (x,y) goes to 0, the denominator should be zero?
As far as (0,0) is concerned, I showed that the partial derivatives at (0,0) are both 0.
To see what the limit of the derivatives is at (0,0), it is best to change to polar coordinates.
In polar coordinates, , and
The derivative becomes
Because of the factor, the limit, as r goes to 0, is 0, no matter what is. Because, in polar coordinates, r alone measures the distance from (0,0), that is enough to show that the limit is 0.
I'll let you do the same for the other partial derivative.