both sets are both open (definition of topology). In particular, they are complements of one another, thus the complement of each is open and hence each one is also closed. The closure of a closed set is itself.
So you mean like ?
1) Suppose were a "point of adherence" as you guys call them apparently. Then for any open U containing x, you need but this is clearly not possible. So the set of all points of adherence of is .
2) Similarly suppose were a "point of adherence." Then for any open U containing x, . So every point in X is a point of adherence, so yeah, you are done.