lim（x→infinity） x^2sin(x) / 1-cosx
how to show that limit is 0??
attempt: i multiplied the bottom by 1+cosx
but i dont know how to carry on. anybody can help me????many thanks
Is your question exactly show the lim (x-> infinity) f(x) = 0
where f(x) =
(x^2)Sinx
1-Cosx
?
______
as
Sinx / (1-Cosx) = Cot (x/2) if that helps
therefore (x^2)Cot (x/2)
which leads me to believe that there doesnt exist a limit at all.
I could be wrong.