Thread: [SOLVED] limits

lim（x→infinity） x^2sin(x) / 1-cosx

how to show that limit is 0??

attempt: i multiplied the bottom by 1+cosx
but i dont know how to carry on. anybody can help me????many thanks

Is your question exactly show the lim (x-> infinity) f(x) = 0

where f(x) =

(x^2)Sinx
1-Cosx

?
______

as
Sinx / (1-Cosx) = Cot (x/2) if that helps

therefore (x^2)Cot (x/2)


which leads me to believe that there doesnt exist a limit at all.

I could be wrong.

Is your question .

If so, then consider this:

my mistake
it is actually x tends to 0

and i sorted out myself. thanks for those who paid attention