if and then prove that the equation : has a root,by using the completeness axiom in real Nos
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The solution of any of this kind of equations is:
so if u have
then x1 and x2 will be real numbers.
Have a nice day,
I am sorry, you have misread my post, i said prove the existence by using the completeness axiom.
To use the square root you must prove 1st that it exists.
How do you know that for all a, b, c and such that
and : exists??
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