Let p(x) be an odd-degree polynomial function. Prove that p(x)=0 has at least one real solution
Not sure if there is a formal proof of this, but one can see that asthen
and as
then
. (assuming leading coefficient is positive, if negative its just the other way around)
By definition any polynomial is continuous onand thus by the IVT we can say there exists at least one
such that
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