The limit, as n approaches infinity, of (1 + (1/n))^n = e (by e, I mean 2.71828). Use this to find the limit of the following sequence: sn = ((n+2)/(n+1))^(n+3)
Follow Math Help Forum on Facebook and Google+
Originally Posted by bearej50 The limit, as n approaches infinity, of (1 + (1/n))^n = e (by e, I mean 2.71828). Use this to find the limit of the following sequence: sn = ((n+2)/(n+1))^(n+3)
Originally Posted by bearej50 The limit, as n approaches infinity, of (1 + (1/n))^n = e (by e, I mean 2.71828). Use this to find the limit of the following sequence: sn = ((n+2)/(n+1))^(n+3) note that what you have is now, do you see how to use what you were given?
View Tag Cloud