gamma function

**math_help** · March 24th 2009, 03:37 AM

So I got a) to be 4!

for b) do I use the same mathod, i.e gamma(n + 1) = n! ?

**Opalg** · March 24th 2009, 04:02 AM

For (b), use the fact that $\Gamma(r+1) = r\Gamma(r)$ . (So for example $\Gamma\bigl(\tfrac{12}5\bigr) = \tfrac75\Gamma\bigl(\tfrac75\bigr) = \ldots$ .)

For (c), use the same method, starting with the fact that $\Gamma\bigl(\tfrac12\bigr) = \sqrt\pi$ .

**mr fantastic** · March 24th 2009, 04:11 AM

Originally Posted by math_help

So I got a) to be 4! Mr F says: Correct.

for b) do I use the same mathod, i.e gamma(n + 1) = n! ?

b) Use $\Gamma (z + 1) = z \Gamma (z)$ .

c) Several approaches are possible eg. Use $\Gamma (z + 1) = z \Gamma (z)$ and $\Gamma \left( \frac{1}{2} \right) = \sqrt{\pi}$ .

**math_help** · March 24th 2009, 09:58 AM

thankyou, makes it very simple now!

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