Show that
part a)
sin(x+iy) = sin x cosh y+ i cos x sinh y
using complex exponentials
This is what i got so far
LHS
sin(x+iy)
RHS
sin x cosh y + i cos x sinh y
when i combine(cross multiply) both the RHS equation i get
Which is equal to
LHS = RHS
part b)
If z = x+iy with x and y real and if sin(z) = 2, deduce that cos x = 0
how do I go upon that?