lim log(sinh(z)) z->pi i/2
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Originally Posted by Richmond lim log(sinh(z)) z->pi i/2 Hint:
Originally Posted by Richmond lim log(sinh(z)) z->pi i/2 Note that So, Since , we see that However, I think you're dealing with the Principal Logarithm. So, we should say that Does this make sense?
I've got till Log(i) I'm not sure what is the Principal Logarithm but I'll try search around the net about it. I think this is what I'm looking for. Thanks again for your help. Greatly appreciated. and thanks to Jhevon too. Prefer to work with
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