Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1
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Originally Posted by mancillaj3 Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1 This is because . Therefore, .
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