Thread: need help on analysis

Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1

Originally Posted by mancillaj3

Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1

This is because .
Therefore, .