Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1

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- Mar 1st 2009, 12:01 AMmancillaj3need help on analysis
Show that if f and g are one-to-one functions such that f (compose)g is defined, then (f (compose)g)^-1= g^-1(compose)f^-1

- Mar 1st 2009, 09:44 AMThePerfectHacker