# parabolic or planar points

Defition: A point of a surface is parabolic if $det(dN_p) = 0$ with $dN_p$ =/= $0$. A point of a surface is planar if $dN_p = 0$.
Let the surface be parametrized by $F(u,v), \ (u,v)\in D$ and the curve by $x(t)=F(u(t),v(t)), \ t\in I$.
Since $x$ is also a plane curve, we have that the binormal vector $b(t)$ satisfies $b(t)=\pm N(u(t),v(t))$ and that $b'=0$ (as there is no torsion). So for points $p$ along the curve $0=b'=N_uu'+N_vv'={\rm d}N_p(u',v')=0$. Now this gives $\{N_u,N_v\}$ are linearly dependent at $p$, so if they are not zero (and the point $p$ planar) then ${\rm det}[{\rm d}N_p]=0$ (and so the point is parabolic).