# Torus T^2 homeomorphic to S^1 x S^1

• Mar 19th 2014, 04:50 PM
Bernhard
Torus T^2 homeomorphic to S^1 x S^1
I am reading Martin Crossley's book, Essential Topology.

Example 5.43 on page 74 reads as follows:

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I am really struggling to get a good sense of why/how/wherefore Crossley came up with the maps f and g in EXAMPLE 5.43. How did he arrive at these maps?

Why/how does f map $S^1 \times S^1$ onto $T^2$ and how does one check/prove that this is in fact a valid mapping between these topological spaces.

Can anyone help in making the origins of these maps clear or perhaps just indicate the logic behind their design and construction? I am completely lacking a sense or intuition for this example at the moment ... ...

Definitions for $T^2$ and $S^1$ are as follows:

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My ideas on how Crossley came up with f and g are totally bankrupt ... but to validate f (that is to check that it actually maps a point of $S^1 \times S^1$ onto $T^2$ - leaving out for the moment the concerns of showing that f is a continuous bijection ... ... I suppose one would take account of the fact that (x,y) and (x',y') are points of TEX] S^1 [/TEX] and so we have:

$x^2 + y^2 = 1$ ... ... ... ... (1)

and

$x'^2 + y'^2 = 1$ ... ... ... ... (2)

Then, keeping this in mind check that

$((x' +2)x, (x' +2)y, y'$ is actually a point on the equation for $T^2$, namely:

$x^2 + y^2 + z^2 - 4 \sqrt{x^2 + y^2} = -3$ ... ... ... (3)

SO in (3) we must:

- replace x by (x' +2)x
- replace y by (x' +2)y
- replace z by y'

and then simplify and if necessary use (1) (2) to finally get -3.

Is that correct? Or am I just totally confused http:///images/smilies/smile.png ?