prove that Δ.(ΨΔφ x φΔΨ)=0 where Δ is delta. anybody help plz
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Hey mathgeni04. Hint: Expand all the vectors out in terms of <x,y,z> terms and use the definition of the dot and cross products.
Originally Posted by MathGeni04 prove that Δ.(ΨΔφ x φΔΨ)=0 where Δ is delta. anybody help plz I do not disagree with reply #2 but I do wonder if by you really mean That is 'nabla' or the del operator. If not what does mean?
\Delta is del operator.
Originally Posted by MathGeni04 prove that Δ.(ΨΔφ x φΔΨ)=0 where Δ is delta. anybody help plz I'm confused here. If φ and Ψ are functions then what does the operator x represent if not simple multiplication?
So you really mean " "?
Thanks HallsofIvy. If that were the case then the whole thing makes sense, if it's an actual identity that is.
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