If you know that f is monotone, then it's trivial: apply n times the function f to both sides of . And converges by the monotone convergence theorem.
Let be an isometry in a metric space . Suppose
Could you explain to me why the sequence is monotone and why does it converge with respect to the usual topology of and also with respect to and, in particular, it satisfies the condition of Cauchy?
I know that since isometry is a continuous and bijective function, it must be monotone. We put , so it must be increasing. But I can't figure out why
Could you help me with that? I would really appreciate a thorough explanation, because I can't find anything about isometry composition anywhere.
Thank you.
If you know that f is monotone, then it's trivial: apply n times the function f to both sides of . And converges by the monotone convergence theorem.