Show the following Leibniz Rule for directional derivatives holds.

Given v ∈ T_p(M) we have v[fg]=v[f]g(p)+f(p)v[g]

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- Mar 29th 2013, 06:10 PMhenderson7878Leibniz Rule for Directional Derivatives
Show the following Leibniz Rule for directional derivatives holds.

Given v ∈ T_p(M) we have v[fg]=v[f]g(p)+f(p)v[g] - Jan 27th 2015, 07:19 AMRebesquesRe: Leibniz Rule for Directional Derivatives
$\displaystyle v(fg)=\frac{d}{dt}\bigg\vert_0(fg)(\gamma(t)) = \ldots$