Limit of a strange sequence

Define sequence by a_0 = 1 and a_(n + 1) = cos(a_(n)/2). Given that |cos(x) - cos(y)| < (or equal to) |x - y| use this to show that cos(a_n/2) -> cos(a/2).

Not exactly sure how to get this. I'm probably being inane here. This question comes under Cauchy sequences..

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Originally Posted by Femto

Define sequence by a_0 = 1 and a_(n + 1) = cos(a_(n)/2). Given that |cos(x) - cos(y)| < (or equal to) |x - y| use this to show that cos(a_n) -> cos(a/2).
Not exactly sure how to get this. I'm probably being inane here. This question comes under Cauchy sequences..

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@Femto please review your post.
Is it

If so, what is in that?

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Originally Posted by Plato

@Femto please review your post.
Is it

If so, what is in that?

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No it's not. I've written it wrong - it should be cos(an/2)

Quote:

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Originally Posted by Femto

No it's not. I've written it wrong - it should be cos(an/2)

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What should be cos(an/2)? That makes no sense.
Please rewrite the entire question.

Done

Great! But what in the world was "a"? You never did say that!