Limit of a strange sequence

Define sequence by a_0 = 1 and a_(n + 1) = cos(a_(n)/2). Given that |cos(x) - cos(y)| < (or equal to) |x - y| use this to show that cos(a_n/2) -> cos(a/2).

Not exactly sure how to get this. I'm probably being inane here. This question comes under Cauchy sequences..

Re: Limit of a strange sequence

Quote:

Originally Posted by

**Femto** Define sequence by a_0 = 1 and a_(n + 1) = cos(a_(n)/2). Given that |cos(x) - cos(y)| < (or equal to) |x - y| use this to show that cos(a_n) -> cos(a/2).

Not exactly sure how to get this. I'm probably being inane here. This question comes under Cauchy sequences..

@Femto please review your post.

Is it $\displaystyle \left(\cos\left(a_n\right)\right)\to\cos\left( \frac{a}{2} \right)~?$

If so, what is $\displaystyle a$ in that?

Re: Limit of a strange sequence

Quote:

Originally Posted by

**Plato** @Femto please review your post.

Is it $\displaystyle \left(\cos\left(a_n\right)\right)\to\cos\left( \frac{a}{2} \right)~?$

If so, what is $\displaystyle a$ in that?

No it's not. I've written it wrong - it should be cos(an/2)

Re: Limit of a strange sequence

Quote:

Originally Posted by

**Femto** No it's not. I've written it wrong - it should be cos(an/2)

What should be cos(an/2)? That makes no sense.

Please rewrite the entire question.

Re: Limit of a strange sequence

Re: Limit of a strange sequence

Great! But what in the world was "a"? You never did say that!