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Thread: a,b,c are vectors. How to prove vector b = c, given a.b = a.c and axb = axc?

  1. #1
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    a,b,c are vectors. How to prove vector b = c, given a.b = a.c and axb = axc?

    a,b,c are vectors. How to prove vector b = c, given a.b = a.c and axb = axc?
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    Re: a,b,c are vectors. How to prove vector b = c, given a.b = a.c and axb = axc?

    I think we need an additional assumption that $\displaystyle \mathbf{a} \ne \mathbf{0}$; otherwise the claim is not true.

    So assuming $\displaystyle \mathbf{a} \ne \mathbf{0}$, as a first step let's see if we can show that if $\displaystyle \mathbf{a} \times \mathbf{v} = \mathbf{0}$ and $\displaystyle \mathbf{a} \cdot \mathbf{v} = 0$ then $\displaystyle \mathbf{v} = \mathbf{0}$.

    We have
    $\displaystyle \mathbf{0} = \mathbf{v} \times (\mathbf{a} \times \mathbf{v}) = \mathbf{a} (\mathbf{v} \cdot \mathbf{v}) - \mathbf{v} (\mathbf{a} \cdot \mathbf{v}) = \mathbf{a} (\mathbf{v} \cdot \mathbf{v}) - \mathbf{v} (0) = \mathbf{a} (\mathbf{v} \cdot \mathbf{v}) $
    so
    $\displaystyle \mathbf{v} \cdot \mathbf{v} = 0$, hence $\displaystyle \mathbf{v} = \mathbf{0}$.

    Finally, to show that if $\displaystyle \mathbf{a} \cdot \mathbf{b} = \mathbf{a} \cdot \mathbf{c}$ and $\displaystyle \mathbf{a} \times \mathbf{b} = \mathbf{a} \times \mathbf{c}$ then $\displaystyle \mathbf{b} = \mathbf{c}$, let $\displaystyle \mathbf{v} = \mathbf{a} - \mathbf{c}$ above.
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