lim(n->∞)[(1+3+5+.......(2n+1)]/n^2]^(3-2n)
I do not know how to solve it, you give me a detailed answer?
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lim(n->∞)[(1+3+5+.......(2n+1)]/n^2]^(3-2n)
I do not know how to solve it, you give me a detailed answer?
Show that limit general term of the series approaches infinity and hence summation approaches infinity: