Hi I have a question on graphing this function and its inverse
y =1/3 * e^(x+1)
In working this out I found that the inverse
X= ln(3y)-1
But I do not know how to draw both graph? Can someone help and this is due now
Hi I have a question on graphing this function and its inverse
y =1/3 * e^(x+1)
In working this out I found that the inverse
X= ln(3y)-1
But I do not know how to draw both graph? Can someone help and this is due now