Hi I have a question on graphing this function and its inverse
y =1/3 * e^(x+1)
In working this out I found that the inverse
X= ln(3y)-1
But I do not know how to draw both graph? Can someone help and this is due now (Worried)
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Hi I have a question on graphing this function and its inverse
y =1/3 * e^(x+1)
In working this out I found that the inverse
X= ln(3y)-1
But I do not know how to draw both graph? Can someone help and this is due now (Worried)
This question has nothing to do with "differential geometry" and was also posted in another sub-forum. This should be deleted.