# Modulus of continuity is continuous?

• Jun 7th 2012, 11:53 AM
Modulus of continuity is continuous?
Hey,

I'm currently reading a book on convergence of probability measures, and there is a property that they assert without too many details that I can't manage to work out for myself.

To put you in context, we're in the space $C[0,1]$ of functions $f:[0,1]\to\mathbb{R}$ that are continuous with respect to the standard euclidean metric $d(x,y)=|x-y|$, and we define the metric on $C[0,1]$ to be $\rho(f,g)=\sup_{t\in[0,1]}|f(t)-g(t)|$.

For every $\delta>0$ and $f\in C[0,1]$, define the modulus of continuity $w(f,\delta)$ as

$w(f,\delta)=\sup_{|x-y|<\delta}|f(x)-f(y)|$

In the book, they say that for any fixed $\delta>0$, the function $w(\cdot,\delta):C[0,1]\to\mathbb{R}$ is continuous. Their only argument is that
for any $f,g\in C[0,1]$, we have $|w(f,\delta)-w(g,\delta)|\leq 2\rho(f,g)$. It's easy to see how this implies continuity, but I can't manage to show this inequality myself. Any help or hints would be greatly appreciated.
• Jun 7th 2012, 01:32 PM
girdav
Re: Modulus of continuity is continuous?
We have $|f(x)-f(y)|\leq 2\rho(f,g)+|g(x)-g(y)|$ then take supremum. Switch the roles of $f$ and $g$ to get what you want.

P.S. Which book are you studying?
• Jun 7th 2012, 02:18 PM