Derivative, f(x) question

hi friends

confused here. question is

f(x) = x / (x-1) use the definition of the derivative to determine f ' (x)

I know it has something to do with inverse functions but i dont know how to start.

working as well please so i can follow what your doing :)

thanks

Re: Derivative, f(x) question

Quote:

Originally Posted by

**Hooperoo** f(x) = x / (x-1) use the definition of the derivative to determine f ' (x)

I know it has something to do with inverse functions but i dont know how to start.

working as well please so i can follow what your doing

As written, it has nothing to do with inverse.

You find $\displaystyle {\lim _{h \to 0}}\frac{{f(x + h) - f(x)}}{h}$

Re: Derivative, f(x) question

Quote:

Originally Posted by

**Hooperoo** hi friends

confused here. question is

f(x) = x / (x-1) use the definition of the derivative to determine f ' (x)

I know it has something to do with inverse functions but i dont know how to start.

working as well please so i can follow what your doing :)

thanks

$\displaystyle \displaystyle \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}=\displaystyle \lim_{h \to 0}\frac{\frac{x+h}{x+h-1}-\frac{x}{x-1}}{h}=\displaystyle \lim_{h \to 0} \frac{-1}{(x+h-1)(x-1)}=\frac{-1}{(x-1)^2}$

Re: Derivative, f(x) question

oh poop, sorry bout the inverse thing. getting very confused about whats inverse and whats to do with limits. thank you both!!!