Re: Pre-Image / Image proof

Quote:

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**monster** Question asks, to prove that if f: A -> B and X is a subset of A prove that X is a subset of f^-1( f(X)) i.e that X is a subset of the pre-image of the image of X,

If $\displaystyle x\in X$ then, $\displaystyle f(x)\in f(X)$ . But by definition, $\displaystyle f^{-1}(f(X))=\{y\in A:f(y)\in f(X)\}$ , then, $\displaystyle x$ satisfies the condition for being in $\displaystyle f^{-1}(f(X))$ . As a consequence, $\displaystyle X\subset f^{-1}(f(X))$ .