For $\displaystyle \delta \mathbb{R}\rightarrow \mathbb{R}^2,\ t\ =\ \delta (t)\ =\ (cosh(2t-2),sin(2\pi t^2))$ find the tangent line and the normal line passing through $\displaystyle \delta(t_0),t_0\ =\ 1$

So i think the tangent line is $\displaystyle T\delta (t_0)\ =\ \delta' (t_0)s\ +\ \delta (t_0)$

However Im clueless as to how to find the normal line.