it's ok apparently, after pluggin in the to into the tangent equation to get Tdelta(to) = (x,y)s + (a,b) the normal line is simply Ndelta(to) = (-y,x)s + (a,b).
ps it was meant to say deltaR rightarrow R to the power of 2 not that weird symbol.
For find the tangent line and the normal line passing through
So i think the tangent line is
However Im clueless as to how to find the normal line.
it's ok apparently, after pluggin in the to into the tangent equation to get Tdelta(to) = (x,y)s + (a,b) the normal line is simply Ndelta(to) = (-y,x)s + (a,b).
ps it was meant to say deltaR rightarrow R to the power of 2 not that weird symbol.
will be a two dimensional vector- the normal will be perpendicular to that so you just need a vector perpendicular to . In two dimensions, that's easy. A normal to the vector <a, b> is <b, -a>.