LET f is Lebesgue Integrable on A where m(A) is finite, Prove that f must be finite almost everywhere on A.
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and . Since , and you can conclude.
Originally Posted by girdav and . Since , and you can conclude. ?? or union??
Originally Posted by younhock ?? or union?? No, it's the intersection, since if then in greater than each integer.
Originally Posted by girdav No, it's the intersection, since if then in greater than each integer. Oh yes i get this. But why is ?
Originally Posted by girdav OKAY!! THANKS a lot!!!!!
And note that the result is true for a -finite measured space , i.e. a space such that we can find a countable partition of into sets of finite measure (for example with Lebesgue measure).
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