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Math Help - Verify that R^3\{2 points} is homotopy equivalent to S^2 V S^2

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    Verify that R^3\{2 points} is homotopy equivalent to S^2 V S^2

    I need to show that $\mathbb{R}^3\backslash A$ where $A$ is two distinct points is homotopically equivalent to $S^2\vee S^2$. I can see this geometrically but am finding it difficult to come up with an explicit proof. Trying to find a deformation retraction to the two spheres but I can't work out the actual equations. Help please!
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    MHF Contributor Drexel28's Avatar
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    Re: Verify that R^3\{2 points} is homotopy equivalent to S^2 V S^2

    Quote Originally Posted by alsn View Post
    I need to show that $\mathbb{R}^3\backslash A$ where $A$ is two distinct points is homotopically equivalent to $S^2\vee S^2$. I can see this geometrically but am finding it difficult to come up with an explicit proof. Trying to find a deformation retraction to the two spheres but I can't work out the actual equations. Help please!
    You're actually supposed to find the explicit deformation retract--blah, sounds like a Hatcher problem. Try to find an explicit map that does the following. First try extending from each of the balls outwards (in each direction not facing the other ball) a line and imagine that you are shrinking \mathbb{R}^3 along those lines by a factor of t, etc. From there you'll have to make the shapes right.
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    Re: Verify that R^3\{2 points} is homotopy equivalent to S^2 V S^2

    Quote Originally Posted by Drexel28 View Post
    You're actually supposed to find the explicit deformation retract--blah, sounds like a Hatcher problem. Try to find an explicit map that does the following. First try extending from each of the balls outwards (in each direction not facing the other ball) a line and imagine that you are shrinking \mathbb{R}^3 along those lines by a factor of t, etc. From there you'll have to make the shapes right.
    I just emailed my lecturer and he said it doesn't have to be an explicit equation. pheww. so i'm guessing i just have to describe the deformation retraction... which seems pretty easy.
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