Convergent Series and Partial Sums

**H12504106** · October 8th 2011, 04:47 AM

I have a solution to the following problem but I am not sure whether it is correct or not. Can someone help me check my solution. Thanks! (The series in this question are all infinite series)

Question: Let $\sum_{n=1} a_n$ and $\sum_{n=1} b_n$ be convergent series. For each $n \in \mathbb{N}$ , let $c_{2n-1} = a_n$ and $c_{2n} = b_n$ . Prove that $\sum_{n=1} c_n$ converges.

Solution: Let $S_n, T_n, R_n$ be the partial sums of the series $\sum_{n=1} a_n, \sum_{n=1} b_n, \sum_{n=1} c_n$ respectively. Now $(R_{2n-1}) = c_1 + c_2 +...+ c_{2n-1} = (a_1 +...+ a_n)+ (b_1 +...+b_{n-1}) = S_n +T_{n-1}$ . Similarily, $(R_{2n}) = c_1 + c_2 +...+ c_{2n-1} + c_{2n} = (a_1 +...+ a_n)+ (b_1 +...+b_n) = S_n +T_n$ . Since $\sum_{n=1} a_n$ and $\sum_{n=1} b_n$ converges, the sequence $(S_n)$ and $(T_n)$ converges. Since $(R_{2n-1})$ and $(R_{2n})$ converges to the same value, $(R_n)$ converges. Hence, the series $\sum_{n=1} c_n$ converges.

**girdav** · October 8th 2011, 07:17 AM

Yes, it's correct.

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