A familyof sets generates a topology on
just in case:
(1);
(2)![]()
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such that
;
(3)for
![]()
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such that
.
Your collection satisfies these requirements. In fact, notice that the second term of the union is superfluous, and that. Given that
is finite, this means
, i.e. it generates the discrete topology.
I'm not sure what you mean by realizing a cover of a family of sets though.
Thank you for help!
Could you correct me if I am wrong in the following:
Let me illustrate examples geometrically.
Given X={a, b, c}
the topological base is
={{B_a},{B_b},{B_c},{B_a,B_b},{B_b,B_c}}
,
for
it is:
={{B_a},{B_b},{B_c}}
B_x - a ball for x