Thread: Difficult Numerical Analysis Problem

Consider a computer using a positive binary floating point representation with n bits of precision in the significand. Assume that rounding is used in going from a number x outside the computer to its floating point approximation fl(x) inside the computer.

Show that:

-2^(e-n) <= x - fl(x) <= 2^(e-n)

(e != 2.71 in this case. ---> -126 <= e <= 127)

Please help. I havnt a clue... Thanks