Showing f is continuous

**mathshelpee** · September 3rd 2011, 12:57 PM

Hey,

I am able to show how f is continuous if the domain is a discrete space. However, in this case the domain is a metric space. Therefore what would be the easiest way to show that f is continuous in this case.

Thanks

http://i53.tinypic.com/iemnv6.jpg

**girdav** · September 3rd 2011, 01:17 PM

Show that $f$ is Lipschitz continuous thanks to the triangular inequality.

**Plato** · September 3rd 2011, 01:55 PM

Originally Posted by mathshelpee

Hey,

I am able to show how f is continuous if the domain is a discrete space. However, in this case the domain is a metric space. Therefore what would be the easiest way to show that f is continuous in this case.Thanks
http://i53.tinypic.com/iemnv6.jpg

Do you know the theorem: If $a,~b,~\&~x_0$ are points in a metric space $X$ then $\left| {d(a,x_0 ) - d(b,x_0 )} \right| \leqslant d(a,b)$ .

Using that you can see if $\varepsilon > 0$ let $\delta=\varepsilon/2$ .
Now if $d(a,b)<\delta$ then $\left| {d(a,x_0 ) - d(b,x_0 )} \right| \leqslant d(a,b)< \varepsilon .$

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