Find the limit:

(2pi-6) + [(pi -6)^2] / pi + [(pi-6)^3] / pi^2 + ...

I see that, except for the first which is positive, this is alternating between positive and negative terms, but how do I find the limit?

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- Aug 30th 2011, 03:02 PMveronicak5678Limit of a Series
Find the limit:

(2pi-6) + [(pi -6)^2] / pi + [(pi-6)^3] / pi^2 + ...

I see that, except for the first which is positive, this is alternating between positive and negative terms, but how do I find the limit? - Aug 30th 2011, 03:49 PMPlatoRe: Limit of a Series
- Aug 30th 2011, 05:16 PMveronicak5678Re: Limit of a Series
So if it is decreasing and null, we know it converges, but how do we find the actual limit?