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Math Help - prove this representation also work!

  1. #1
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    prove this representation also work!

    if z = x + iy
    prove:z = re^(iθ) also work

    Also,prove: dz= e^(iθ) dr + ire^(iθ)dθ
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  2. #2
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    Re: prove this representation also work!

    Polar form of a complex number z = x + iy is
    z = r[ cos(theta) + i sin(theta) ]
    and cos(theta) + i sin(theta) = e^i(theta)
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  3. #3
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    Re: prove this representation also work!

    also,please prove : dz= e^(iθ) dr + ire^(iθ)dθ
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  4. #4
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    Re: prove this representation also work!

    again from polar for of z dz = [ cos(theta) + i sin(theta) ] dr + r [-sin(theta) + i cos(theta)] d(theta)

    dz = [ cos(theta) + i sin(theta) ] dr + i r [ cos(theta) + i sin(theta)] d(theta) that gives required result
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  5. #5
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    Re: prove this representation also work!

    Quote Originally Posted by waqarhaider View Post
    again from polar for of z dz = [ cos(theta) + i sin(theta) ] dr + r [-sin(theta) + i cos(theta)] d(theta)

    dz = [ cos(theta) + i sin(theta) ] dr + i r [ cos(theta) + i sin(theta)] d(theta) that gives required result
    May you put it in latex,please,i have little confused
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  6. #6
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    Re: prove this representation also work!

    Quote Originally Posted by victorlui View Post
    May you put it in latex,please,i have little confused
    What was posted is perfectly readable. The problem is, perhaps, you are out of your depth trying to understand things that depend on pre-requisite knowledge you do not currently have.
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