# Extend a function to an impair one.

• Jul 2nd 2011, 12:39 PM
orbit
Extend a function to an impair one.
Hello, I have been ask to extend the following function to [-1,1] such that the new functions becomes impair. The problem is that I dont know how to do it. Thanks!
• Jul 2nd 2011, 09:31 PM
FernandoRevilla
Re: Extend a function to an impair one.
Quote:

Originally Posted by orbit
Hello, I have been ask to extend the following function to [-1,1] such that the new functions becomes impair. The problem is that I dont know how to do it. Thanks!

In Spanish, función impar is equivalent in English to odd function so, I suppose you mean becomes odd instead of becomes impair . In such a case the problem has no solution because if $\displaystyle f$ is odd then, $\displaystyle f(-0)=-f(0)\Rightarrow f(0)=0$ .
• Jul 3rd 2011, 12:43 PM
orbit
Re: Extend a function to an impair one.
Quote:

Originally Posted by FernandoRevilla
In Spanish, función impar is equivalent in English to odd function so, I suppose you mean becomes odd instead of becomes impair . In such a case the problem has no solution because if $\displaystyle f$ is odd then, $\displaystyle f(-0)=-f(0)\Rightarrow f(0)=0$ .

Hello,

thanks. The correct word is odd.

And thanks for letting me know the problem has no solution. The correct question is now available.
• Jul 3rd 2011, 12:49 PM
orbit
Re: Extend a function to an impair one.
Quote:

Originally Posted by orbit
Hello, I have been ask to extend the following function to [-1,1] such that the new functions becomes impair. The problem is that I don`t know how to do it. Thanks!

This is the correct question. Sorry!
• Jul 3rd 2011, 01:16 PM
FernandoRevilla
Re: Extend a function to an impair one.
Quote:

Originally Posted by orbit
This is the correct question. Sorry!

Try it. Remember, $\displaystyle f:[-a,a]\to \mathbb{R}$ is odd iff $\displaystyle f(-x)=-f(x)$ for all $\displaystyle x\in [-a,a]$ .