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**ivinew** Use Cauchy's Integral Formula to evaluate the integral $\displaystyle \oint_{C}f(z)dz$ over a contour C, where C is the boundary of a square with diagonal opposite corners at z = −(1 + i )R and z = (1 + i )R, where R > a > 0, and where $\displaystyle f(z)=\frac{e^z}{z-\frac{i\pi}{4} a}$

I know f(z) would not be analytic at $\displaystyle \frac{i\pi}{4} a$.

Then by Cauchy's Integral Formula:

$\displaystyle f(a) = \frac{1}{2i\pi} \oint_{C}\frac{f(z)}{z-a} $

$\displaystyle f(\frac{i\pi}{4} a) = \frac{1}{2i\pi} \oint_{C}\frac{e^z}{z-\frac{i\pi}{4} a} $

Am I going in the right direction so far?