$\displaystyle exp[2z] + exp[z] + 1 = 0 $

Really not sure how to start this one, i tried breaking it into it's real and imaginary components but didn't get far with that.

$\displaystyle exp[2x] \cdot(cos(2y)+isin(2y)) + exp[x]\cdot(cos(y)+isin(y)) +1 = 0 ?? $

Is it something to do with taking the log?

If so i'm a little lost on how to do it