Show that C[0,1] and C[a,b] are isometric.
A mapping T of X into X' is said to be isometric if for all x, y in X
C is continous [0,1] and [a,b] closed interval..
The distance on Function space C[a,b] is d(x,y)=max|x(t)-y(t)|
I couldnt procced from here....i need some help....
Thank u very much...
But how can we prove that the map is bijective...i mean how can we see that it is one-to-one and onto...
Have you tried to prove it?
Originally Posted by kinkong
yes i thought about it..but i couldnt find a way...please can u help me...