I'm having a hard time showing that fails to converge absolutely, any insight would be greatly appreciated.

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- May 14th 2011, 06:11 PMeastmanAbsolute Convergence of Integral
I'm having a hard time showing that fails to converge absolutely, any insight would be greatly appreciated.

- May 14th 2011, 06:57 PMProve It
Try writing as a Taylor Series, then simplifying .

- May 14th 2011, 07:06 PMJose27
Another way: If you know that is infinite, just apply a change of variables.

- May 15th 2011, 06:57 AMeastmanThanks
Thanks to both of you for your help. I did try one way before I read this, maybe you can tell me this works...

...and then just evaluate, I could be way off. (Wondering) - May 15th 2011, 11:21 AMJose27
- May 15th 2011, 12:40 PMeastman
Sorry, I'm slightly confused, could you elaborate?

- May 15th 2011, 02:23 PMJose27
Disregard the second part of my last message, could you explain how you got the last inequality?

- May 16th 2011, 01:01 PMeastman
You're right the last inequality does not hold, sin vanishes over those intervals.. I ended up doing it with the change of variables like you orginally said. Thanks for your help.